Integrate int(s^2-36)ds

 Exercise

$\int\left(s^2-36\right)ds$

 

Expand the integral $\int\left(s^2-36\right)ds$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately

$\int s^2ds+\int-36ds$

 

The integral $\int s^2ds$ results in: $\frac{s^{3}}{3}$

$\frac{s^{3}}{3}$

 

The integral $\int-36ds$ results in: $-36s$

$-36s$

 

Gather the results of all integrals

$\frac{s^{3}}{3}-36s$

 

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$

$\frac{s^{3}}{3}-36s+C_0$

$\frac{s^{3}}{3}-36s+C_0$

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