Find the integral $\int x^2\sin\left(x^4\right)dx$

Step-by-step Solution

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Final answer to the problem

$\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^nx^{\left(7+8n\right)}}{\left(7+8n\right)\left(2n+1\right)!}+C_0$
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Step-by-step Solution

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  • Integrate by partial fractions
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  • Integrate using tabular integration
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  • Weierstrass Substitution
  • Integrate using trigonometric identities
  • Integrate using basic integrals
  • Product of Binomials with Common Term
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1

Rewrite the function $\sin\left(x^4\right)$ as it's representation in Maclaurin series expansion

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$\int x^2\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^n}{\left(2n+1\right)!}\left(x^4\right)^{\left(2n+1\right)}dx$

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Unlock the first 3 steps of this solution

Learn how to solve problems step by step online. Find the integral int(x^2sin(x^4))dx. Rewrite the function \sin\left(x^4\right) as it's representation in Maclaurin series expansion. Simplify \left(x^4\right)^{\left(2n+1\right)} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 4 and n equals 2n+1. Solve the product 4\left(2n+1\right). Bring the outside term x^2 inside the power serie.

Final answer to the problem

$\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^nx^{\left(7+8n\right)}}{\left(7+8n\right)\left(2n+1\right)!}+C_0$

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Plotting: $\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^nx^{\left(7+8n\right)}}{\left(7+8n\right)\left(2n+1\right)!}+C_0$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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