Find the integral $\int\left(x^5+3x^3-2x\right)\sin\left(3x\right)dx$

Step-by-step Solution

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Final answer to the problem

$-\frac{1}{3}x^5\cos\left(3x\right)+\frac{4}{3}x\cos\left(3x\right)+\frac{5}{9}x^{4}\sin\left(3x\right)-\frac{4}{9}\sin\left(3x\right)-\frac{7}{27}x^3\cos\left(3x\right)+\frac{7}{27}x^{2}\sin\left(3x\right)-\frac{40}{81}x\cos\left(3x\right)+\frac{40}{243}\sin\left(3x\right)+C_0$
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Step-by-step Solution

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  • Integrate by partial fractions
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  • Integrate using tabular integration
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We can solve the integral $\int\left(x^5+3x^3-2x\right)\sin\left(3x\right)dx$ by applying the method of tabular integration by parts, which allows us to perform successive integrations by parts on integrals of the form $\int P(x)T(x) dx$. $P(x)$ is typically a polynomial function and $T(x)$ is a transcendent function such as $\sin(x)$, $\cos(x)$ and $e^x$. The first step is to choose functions $P(x)$ and $T(x)$

Learn how to solve tabular integration problems step by step online.

$\begin{matrix}P(x)=\left(x^5+3x^3-2x\right) \\ T(x)=\sin\left(3x\right)\end{matrix}$

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Learn how to solve tabular integration problems step by step online. Find the integral int((x^5+3x^3-2x)sin(3x))dx. We can solve the integral \int\left(x^5+3x^3-2x\right)\sin\left(3x\right)dx by applying the method of tabular integration by parts, which allows us to perform successive integrations by parts on integrals of the form \int P(x)T(x) dx. P(x) is typically a polynomial function and T(x) is a transcendent function such as \sin(x), \cos(x) and e^x. The first step is to choose functions P(x) and T(x). Derive P(x) until it becomes 0. Integrate T(x) as many times as we have had to derive P(x), so we must integrate \sin\left(3x\right) a total of 6 times. With the derivatives and integrals of both functions we build the following table.

Final answer to the problem

$-\frac{1}{3}x^5\cos\left(3x\right)+\frac{4}{3}x\cos\left(3x\right)+\frac{5}{9}x^{4}\sin\left(3x\right)-\frac{4}{9}\sin\left(3x\right)-\frac{7}{27}x^3\cos\left(3x\right)+\frac{7}{27}x^{2}\sin\left(3x\right)-\frac{40}{81}x\cos\left(3x\right)+\frac{40}{243}\sin\left(3x\right)+C_0$

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Function Plot

Plotting: $-\frac{1}{3}x^5\cos\left(3x\right)+\frac{4}{3}x\cos\left(3x\right)+\frac{5}{9}x^{4}\sin\left(3x\right)-\frac{4}{9}\sin\left(3x\right)-\frac{7}{27}x^3\cos\left(3x\right)+\frac{7}{27}x^{2}\sin\left(3x\right)-\frac{40}{81}x\cos\left(3x\right)+\frac{40}{243}\sin\left(3x\right)+C_0$

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/
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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Tabular Integration

Tabular integration is a special technique to solve certain integrals by parts usually made up of two functions: one polynomial and the other transcendent, like the exponential function or the sine. The method consists of deriving the polynomial function several times (until it becomes zero), and integrating the transcendent function several times. This method is usually applied when both functions can be easily derived and integrated multiple times.

Used Formulas

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