Final answer to the problem
$\frac{1}{4-x}=\lim_{c\to{- \infty }}\left(\left[1\right]_{c}^{3}\right)$
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Step-by-step Solution
How should I solve this problem?
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- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Exact Differential Equation
- Linear Differential Equation
- Separable Differential Equation
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1
Replace the integral's limit by a finite value
$\int\frac{1}{\left(4-x\right)^2}dx=\lim_{c\to{- \infty }}\left(\left[1\right]_{c}^{3}\right)$
2
Solve the integral $\int\frac{1}{\left(4-x\right)^2}dx$ and replace the result in the differential equation
$\frac{1}{4-x}=\lim_{c\to{- \infty }}\left(\left[1\right]_{c}^{3}\right)$
Final answer to the problem
$\frac{1}{4-x}=\lim_{c\to{- \infty }}\left(\left[1\right]_{c}^{3}\right)$