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Expand the integral $\int_{0}^{3}\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}-\frac{\pi }{9}\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{0}^{3}\frac{\pi }{\sqrt{\left(982\right)^{3}}}dx+\int_{0}^{3}-\frac{\pi }{9}dx$
Learn how to solve differential calculus problems step by step online. Integrate the function pi/(982^(3/2))-pi/9 from 0 to 3. Expand the integral \int_{0}^{3}\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}-\frac{\pi }{9}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{3}\frac{\pi }{\sqrt{\left(982\right)^{3}}}dx results in: 3\left(\frac{\pi }{\sqrt{\left(982\right)^{3}}}\right). The integral \int_{0}^{3}-\frac{\pi }{9}dx results in: -\frac{\pi }{3}. Gather the results of all integrals.
