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Integrate the function $\sqrt{5+4x-x^2}$ from $4$ to $4$

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Solution

Videos

Algebra 2 - How to graph a quadratic using a table y = x^2 + 4x -1

https://www.youtube.com/watch?v=SQGShfsW4tk

Algebra 2 - How to write a polynomial in standard form when divided by a number, (2x^4 + 4x - 5) / 4

https://www.youtube.com/watch?v=nSzTK9_lYZw

Pre-Calculus - Operations with functions f(x) = 2x -5 , g(x) = 2-x and f(x) = x^2+6 , g(x) root(1-x)

https://www.youtube.com/watch?v=rthRvbioYyU

Algebra 2 - Learning to solve rational equations in math class ((x+3)/(x‐2)) + (5/(x^2‐4)) = 1

https://www.youtube.com/watch?v=y8p0Tpn3BcI

Algebra 1 - Solve an equation with a rational term 1/x= 3+ 7/x^2+7x ex 2

https://www.youtube.com/watch?v=OjNDpBeMpxI

Calculus - Mulitiplying Rational Expressions, ((x^2 - 2x - 3)/(x^2 - 1)) . ((3x - 3)/(x^2 - 4x + 3))

https://www.youtube.com/watch?v=eB9q_okoWFA

Function Plot

Plotting: $\sqrt{5+4x-x^2}$

Similar Problems Solved

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$\int_2^{\infty}\left(\frac{1}{x^2+6x+5}\right)dx$

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$\int_0^{\infty}\left(\frac{1}{\sqrt{x}+x^2}\right)dx$

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$\int_3^{\infty}4e^{\left(2x-4\right)}dx$

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

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