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Multiply the single term $3x-5$ by each term of the polynomial $\left(2x+3\right)$
Learn how to solve integrals involving logarithmic functions problems step by step online.
$2x\left(3x-5\right)+3\left(3x-5\right)+30\geq 6\left(x^2+3\right)+20+5x$
Learn how to solve integrals involving logarithmic functions problems step by step online. Solve the inequality (2x+3)(3x-5)+30>=6(x^2+3)+205x. Multiply the single term 3x-5 by each term of the polynomial \left(2x+3\right). Multiply the single term 3 by each term of the polynomial \left(3x-5\right). Add the values -15 and 30. Multiply the single term 6 by each term of the polynomial \left(x^2+3\right).