Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for a
- Solve for b
- Solve for x
- Solve for y
- Find the derivative
- Solve by implicit differentiation
- Solve for y'
- Find dy/dx
- Derivative
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A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: $(a-b)^2=a^2-2ab+b^2$
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$\left(a^2+b^2\right)\left(x^2+y^2\right)=\left(ax\right)^2-2axby+\left(by\right)^2+\left(bx+ay\right)^2$
Learn how to solve equations problems step by step online. Solve the equation (a^2+b^2)(x^2+y^2)=(ax-by)^2+(bx+ay)^2. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. The power of a product is equal to the product of it's factors raised to the same power. Move everything to the left hand side of the equation. Multiply the single term x^2+y^2 by each term of the polynomial \left(a^2+b^2\right).
