Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
- Load more...
A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: $(a-b)^2=a^2-2ab+b^2$
Learn how to solve problems step by step online.
$x^2-8x+16+y\leq -12+\left(x-2\right)^2$
Learn how to solve problems step by step online. Solve the inequality (x-4)^2+y<=-12+(x-2)^2. A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. Moving the term 16 to the other side of the inequation with opposite sign. Subtract the values -12 and -16. Expand \left(x-2\right)^2.
