Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve using L'Hôpital's rule
- Solve without using l'Hôpital
- Solve using limit properties
- Solve using direct substitution
- Solve the limit using factorization
- Solve the limit using rationalization
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Load more...
As it's an indeterminate limit of type $\frac{\infty}{\infty}$, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is
Learn how to solve limits by direct substitution problems step by step online.
$\lim_{x\to\infty }\left(\frac{\frac{2x+3}{x}}{\frac{3x+1}{x}}\right)$
Learn how to solve limits by direct substitution problems step by step online. Find the limit of (2x+3)/(3x+1) as x approaches infinity. As it's an indeterminate limit of type \frac{\infty}{\infty}, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is . Separate the terms of both fractions. Simplify the fraction \frac{2x}{x} by x. Evaluate the limit \lim_{x\to\infty }\left(\frac{2+\frac{3}{x}}{3+\frac{1}{x}}\right) by replacing all occurrences of x by \infty .
