Find the limit of $\frac{e^x-1}{2x}$ as $x$ approaches 0

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Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

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Algebra 2 - Find the solutions to the given trinomial - Online Tutor 3x^2 - 2x - 1 = 0

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Function Plot

Plotting: $\frac{e^x-1}{2x}$

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1
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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Limits by L'Hôpital's rule

In mathematics, and more specifically in calculus, L'Hôpital's rule uses derivatives to help evaluate limits involving indeterminate forms.

Used Formulas

See formulas (3)

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