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Find the limit of $\frac{x}{x^2-x}$ as $x$ approaches 0

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Limits by direct substitution | Limits and continuity | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=cfOcOgr0E7U

Limit of (sin x)/x as x approaches 0

https://www.youtube.com/watch?v=5xitzTutKqM

_-substitution: definite integral of exponential function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=1ct7LUx23io

Undefined limits by direct substitution | Limits and continuity | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=JlOyb_RTejo

Calculus - Find the derivative of the inverse of a radical equation, f(x)=sqrt(x^2 +6x); find g'(4)

https://www.youtube.com/watch?v=ErarY1CS-bY

Calculus - Evaluating a limit by rationalizing the radical, lim(x tends to 0) (sqrt(x + 1) - 1)/x

https://www.youtube.com/watch?v=v8dIvXm03dw

Function Plot

Plotting: $\frac{x}{x^2-x}$

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1
2
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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

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