$16-32+8-4-5-6-9+1$
$\frac{1}{2}ln\:\frac{\left(1+x\right)}{1-x}$
$\left(2x^2\right)^2-2\left(2x^2\right)\left(3y^6\right)+\left(3y^6\right)^2$
$5x+45$
$\lim_{x\to-50}\left(\frac{\sqrt{-800x}-200}{x+50}\right)$
$3x^2-4\ge\:5$
$\lim_{x\to-4}\sqrt[3]{\frac{3-4x}{2-x}}$
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