$\left(2x^2-1\right)\left(3x-2\right)$
$2x^2+6x+4\le0$
$\int\frac{2x^2+x+3}{\left(x+1\right)\left(x^2+1\right)}dx$
$\frac{\sec\left(a\right)}{\sin\left(a\right)}-\tan\left(a\right)=\cot a$
$\sin\left(4\right)x=-\cos\left(1\right)^2x+1$
$25x-5$
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