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Find the limit of $\left(1-e^x\right)^{\frac{1}{\ln\left(x\right)}}$ as $x$ approaches 0

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csc

asin

acos

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 Solution

 Formulas

 Videos

Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=TDJ5nXWEkWM

Calculus - Evaluating a limit by rationalizing the radical, lim(x tends to 0) (sqrt(x + 1) - 1)/x

https://www.youtube.com/watch?v=v8dIvXm03dw

Tutorial - Condensing logarithmic expressions ex 12, 1/3(2ln(x+3)+lnx-ln(x^2-1))

https://www.youtube.com/watch?v=l8AE8UzknbY

Tutorial - Condensing logarithmic expressions ex 11, 1/2(3log2(x)-2 log2(z))

https://www.youtube.com/watch?v=doNh13E4XBo

Limit of (sin x)/x as x approaches 0

https://www.youtube.com/watch?v=5xitzTutKqM

L'hospital's Rule Indeterminate Forms, Limits at Infinity, Ln, Trig & Exponential Functions Calculus

https://www.youtube.com/watch?v=thEnl_gCjXA

 Function Plot

Plotting: $\left(1-e^x\right)^{\frac{1}{\ln\left(x\right)}}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Limits by L'Hôpital's rule

In mathematics, and more specifically in calculus, L'Hôpital's rule uses derivatives to help evaluate limits involving indeterminate forms.

 Used Formulas

See formulas (7)

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