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Find the limit of $\left(1-x\right)^{\frac{1}{x}}$ as $x$ approaches 0

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lim

d/dx

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>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

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acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 Solution

 Formulas

 Videos

Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=TDJ5nXWEkWM

Calculus - Evaluating a limit by rationalizing the radical, lim(x tends to 0) (sqrt(x + 1) - 1)/x

https://www.youtube.com/watch?v=v8dIvXm03dw

Tutorial - Condensing logarithmic expressions ex 11, 1/2(3log2(x)-2 log2(z))

https://www.youtube.com/watch?v=doNh13E4XBo

Limit of (sin x)/x as x approaches 0

https://www.youtube.com/watch?v=5xitzTutKqM

_-substitution: definite integral of exponential function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=1ct7LUx23io

Linear approximation of a rational function | Derivative rules | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=vRw4ovZK1CQ

 Function Plot

Plotting: $\left(1-x\right)^{\frac{1}{x}}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Limits by L'Hôpital's rule

In mathematics, and more specifically in calculus, L'Hôpital's rule uses derivatives to help evaluate limits involving indeterminate forms.

 Used Formulas

See formulas (5)

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