$3x^5+2x^2-4x-6x^5-4x^3-7x^2-3x$
$\int\frac{1}{x^2-4x-5}dx$
$10=\log x$
$\int_0^{\infty}\left(\frac{x^3}{e^{x-1}}\right)dx$
$-64-293+18-45-48$
$\int-sec^3xdx$
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