Find the limit of $x^{\frac{1}{x^2-1}}$ as $x$ approaches $1$

Step-by-step Solution

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Final answer to the problem

$\sqrt{e}$
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Step-by-step Solution

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  • Solve using L'Hôpital's rule
  • Solve without using l'Hôpital
  • Solve using limit properties
  • Solve using direct substitution
  • Solve the limit using factorization
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  • Integrate by partial fractions
  • Product of Binomials with Common Term
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1

Rewrite the limit using the identity: $a^x=e^{x\ln\left(a\right)}$

$\lim_{x\to1}\left(e^{\frac{1}{x^2-1}\ln\left(x\right)}\right)$

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$\lim_{x\to1}\left(e^{\frac{1}{x^2-1}\ln\left(x\right)}\right)$

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Learn how to solve problems step by step online. Find the limit of x^(1/(x^2-1)) as x approaches 1. Rewrite the limit using the identity: a^x=e^{x\ln\left(a\right)}. Multiplying the fraction by \ln\left(x\right). Apply the power rule of limits: \displaystyle{\lim_{x\to a}f(x)^{g(x)} = \lim_{x\to a}f(x)^{\displaystyle\lim_{x\to a}g(x)}}. The limit of a constant is just the constant.

Final answer to the problem

$\sqrt{e}$

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Function Plot

Plotting: $x^{\frac{1}{x^2-1}}$

SnapXam A2
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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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