Final answer to the problem
$\ln\left(\frac{e^{2x}\left(x^3-5\right)}{\left(3x+2\right)^4}\right)$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Condense the logarithm
- Expand the logarithm
- Simplify
- Find the integral
- Find the derivative
- Write as single logarithm
- Integrate by partial fractions
- Product of Binomials with Common Term
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1
The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
$\ln\left(\frac{e^{2x}\left(x^3-5\right)}{\left(3x+2\right)^4}\right)$
Final answer to the problem
$\ln\left(\frac{e^{2x}\left(x^3-5\right)}{\left(3x+2\right)^4}\right)$
