Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Condense the logarithm
- Expand the logarithm
- Simplify
- Find the integral
- Find the derivative
- Write as single logarithm
- Integrate by partial fractions
- Product of Binomials with Common Term
- Load more...
The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
Learn how to solve expanding logarithms problems step by step online.
$\log \left(100x^5\sqrt[3]{2-x}\right)-\log \left(7\left(x+4\right)^2\right)$
Learn how to solve expanding logarithms problems step by step online. Expand the logarithmic expression log((100*x^5*(2+-1*x)^(1/3))/(7*(x+4)^2)). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Use the product rule for logarithms: \log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right), where M=x^5 and N=100\sqrt[3]{2-x}. Use the product rule for logarithms: \log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right), where M=\sqrt[3]{2-x} and N=100. Use the product rule for logarithms: \log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right), where M=\left(x+4\right)^2 and N=7.
