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Solve the equation with radicals $\left(\sec\left(2x\right)^2\right)^2+y^{-1}=\sin\left(2u\right)^2$

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Solution

Videos

Algebra 2 - Solve an equation with rational terms (1/r^2) – ((4r–8)/r^2) = 1/r

https://www.youtube.com/watch?v=vCXAv5Ul5OA

Tutorial - Solving logarithmic equations ex 5, log(5-2x)=0

https://www.youtube.com/watch?v=NaxzQH3eqcw

Pre-Calculus - Solving a natural logarithm for the given problem lnx = -1

https://www.youtube.com/watch?v=h6OSBOdaLfI

Algebra 1 - Solve an equation by factoring (v+5)^2 = 0

https://www.youtube.com/watch?v=Pj6lOAT56VI

Calculus - Solving Rational Equations, ((4x + 1)/4) - ((2x + 3)/3) = 7/12

https://www.youtube.com/watch?v=1J6QI7lmlj4

Pre-Calculus - Determining the triple angle of cosine to solve the equation cos(3x)=-1/2

https://www.youtube.com/watch?v=M4ZbUoyVWvE

Function Plot

Plotting: $\left(\sec\left(2x\right)^2\right)^2+y^{-1}-\sin\left(2u\right)^2$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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Main Topic: Equations

In mathematics, an equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. In this situation, variables are also known as unknowns and the values which satisfy the equality are known as solutions.

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