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Solve the quadratic equation $\sqrt{5y^2-14y+13}=\sqrt{5y^2-10y+25}$

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 Solution

 Videos

Algebra 2 - Learn to describe and solve for the zeros using completing the square 4x^2 - 4x - 1 = 0

https://www.youtube.com/watch?v=0lpMs0iXm2E

Algebra 2 - using the square root method to solve a quadratic equation 4x^2 - 4x + 1 = 9

https://www.youtube.com/watch?v=90FQ2oLoEEQ

Pre-Calculus - Using the square root method to solve a quadratic equation, (1/2)x^2 + 3 = 19

https://www.youtube.com/watch?v=dvE_W89LrqA

Algebra 2 - Learning to solve rational equations in math class ((x+3)/(x‐2)) + (5/(x^2‐4)) = 1

https://www.youtube.com/watch?v=y8p0Tpn3BcI

Algebra 2 - Solve an equation with rational terms (1/r^2) – ((4r–8)/r^2) = 1/r

https://www.youtube.com/watch?v=vCXAv5Ul5OA

Algebra 2 - Learn how solve a quadratic by completing the square with fractions, x^2 + 3x + 6 = 0

https://www.youtube.com/watch?v=KWBr5zM3tXs

 Function Plot

Plotting: $\sqrt{5y^2-14y+13}-\sqrt{5y^2-10y+25}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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