 Calculators  AI Whiteboard  Worksheets & Tests Go Premium  Topics

 Tap to take a pic of the problem

Solve the product power $\sqrt{1000x^9y^{18}}$

Related Videos

Go!

Symbolic mode

Text mode



Go!

1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 Solution

 Videos

Tutorial - Condensing logarithmic expressions ex 11, 1/2(3log2(x)-2 log2(z))

https://www.youtube.com/watch?v=doNh13E4XBo

Algebra 2 - Simplifying a rational exponent with a rational base, (4/3)^(-1/2)

https://www.youtube.com/watch?v=8s2xAi_B4uc

Algebra 2 - Simplifying an expression with rational and negative exponents (x^(1/6) y^(1/3))^-18

https://www.youtube.com/watch?v=42cGdWlTRvc

Algebra 2 - Multiplying two exponents with rational powers, then simplifying, 2x^(2/5) . 6x^(1/4)

https://www.youtube.com/watch?v=ITQM50h5BlY

Algebra 2 - Learn how solve an equation with a rational power by cubing both sides y^(1/3) -7 = 0

https://www.youtube.com/watch?v=yzxApOS1ZMY

How to factor a quadratic equation when c=0 - Free Math Help - Online Tutor

https://www.youtube.com/watch?v=YWh2eUXonC0

 Function Plot

Plotting: $\sqrt{1000}\sqrt{x^{9}}y^{9}$

SnapXam A²

Answer Assistant

beta
Got a different answer? Verify it!



Go!

1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Power of a product

The power of a product of factors is equal to the product of each factor to the same power: $\left(b\cdot c\right)^n=b^n\cdot c^n$.

 Related Topics