Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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Apply the formula: $a\log_{b}\left(x\right)$$=\log_{b}\left(x^a\right)$
The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
Rewrite the number $0$ as a logarithm of base $10$
Any expression (except $0$ and $\infty$) to the power of $0$ is equal to $1$
Rewrite the number $0$ as a logarithm of base $10$
For two logarithms of the same base to be equal, their arguments must be equal. In other words, if $\log(a)=\log(b)$ then $a$ must equal $b$
Multiply both sides of the equation by $x+6$
Any expression multiplied by $1$ is equal to itself
Multiply both sides of the equation by $x+6$
Move everything to the left hand side of the equation
Factor the trinomial $x^2-x-6$ finding two numbers that multiply to form $-6$ and added form $-1$
Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values
Break the equation in $2$ factors and set each factor equal to zero, to obtain simpler equations
Solve the equation ($1$)
We need to isolate the dependent variable $x$, we can do that by simultaneously subtracting $2$ from both sides of the equation
Canceling terms on both sides
Solve the equation ($2$)
We need to isolate the dependent variable $x$, we can do that by simultaneously subtracting $-3$ from both sides of the equation
Canceling terms on both sides
Combining all solutions, the $2$ solutions of the equation are
Verify that the solutions obtained are valid in the initial equation
The valid solutions to the logarithmic equation are the ones that, when replaced in the original equation, don't result in any logarithm of negative numbers or zero, since in those cases the logarithm does not exist
