Final answer to the problem
$x=\frac{8+\sqrt{128}}{2},\:x=\frac{8-\sqrt{128}}{2}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Apply the formula: $a\log_{b}\left(x\right)$$=\log_{b}\left(x^a\right)$
$\log_{4}\left(\left(2-x\right)^2\right)-\log_{4}\left(x+5\right)=1$
Learn how to solve problems step by step online.
$\log_{4}\left(\left(2-x\right)^2\right)-\log_{4}\left(x+5\right)=1$
Learn how to solve problems step by step online. Solve the logarithmic equation 2log4(2+-1*x)-log4(x+5)=1. Apply the formula: a\log_{b}\left(x\right)=\log_{b}\left(x^a\right). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Expand \left(2-x\right)^2. Take the variable outside of the logarithm.
Final answer to the problem
$x=\frac{8+\sqrt{128}}{2},\:x=\frac{8-\sqrt{128}}{2}$
