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Applying the trigonometric identity: $\sec\left(\theta \right)^2 = 1+\tan\left(\theta \right)^2$
$4\left(1+\tan\left(x\right)^2\right)-7\tan\left(x\right)^2=3$
Why is tan(x)^2+1 = sec(x)^2 ?
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$4\left(1+\tan\left(x\right)^2\right)-7\tan\left(x\right)^2=3$
Learn how to solve problems step by step online. Solve the trigonometric equation 4sec(x)^2-7tan(x)^2=3. Applying the trigonometric identity: \sec\left(\theta \right)^2 = 1+\tan\left(\theta \right)^2. Multiply the single term 4 by each term of the polynomial \left(1+\tan\left(x\right)^2\right). Combining like terms 4\tan\left(x\right)^2 and -7\tan\left(x\right)^2. We need to isolate the dependent variable x, we can do that by simultaneously subtracting 4 from both sides of the equation.
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