Solve the differential equation $4dy=e^{\left(-2x-3y\right)}dx$

Step-by-step Solution

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Final answer to the problem

$y=\frac{\ln\left(3\left(\frac{-1}{8e^{2x}}+C_0\right)\right)}{3}$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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1

Divide both sides of the equation by $dx$

$\frac{4dy}{dx}=e^{\left(-2x-3y\right)}\frac{dx}{dx}$

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$\frac{4dy}{dx}=e^{\left(-2x-3y\right)}\frac{dx}{dx}$

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Learn how to solve problems step by step online. Solve the differential equation 4dy=e^(-2x-3y)dx. Divide both sides of the equation by dx. Simplify the fraction \frac{dx}{dx} by dx. Any expression multiplied by 1 is equal to itself. Rewrite the differential equation.

Final answer to the problem

$y=\frac{\ln\left(3\left(\frac{-1}{8e^{2x}}+C_0\right)\right)}{3}$

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Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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Function Plot

Plotting: $4dy-e^{\left(-2x-3y\right)}dx$

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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