Final answer to the problem
$2x-3+\frac{-5}{2x-1}$
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Step-by-step Solution
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- Write in simplest form
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
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- Integrate by parts
- Integrate using tabular integration
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- Weierstrass Substitution
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1
Divide $4x^2-8x-2$ by $2x-1$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}-1;}{\phantom{;}2x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}-1\overline{\smash{)}\phantom{;}4x^{2}-8x\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}-1;}\underline{-4x^{2}+2x\phantom{;}\phantom{-;x^n}}\\\phantom{-4x^{2}+2x\phantom{;};}-6x\phantom{;}-2\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-1-;x^n;}\underline{\phantom{;}6x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}6x\phantom{;}-3\phantom{;}\phantom{;}-;x^n;}-5\phantom{;}\phantom{;}\\\end{array}$
2
Resulting polynomial
$2x-3+\frac{-5}{2x-1}$
Final answer to the problem
$2x-3+\frac{-5}{2x-1}$
