Solve the rational equation $5\left(a+2\right)=\frac{40}{a}+\frac{2a}{3}$

Step-by-step Solution

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Final answer to the problem

$a=-\frac{15}{13}+\sqrt{2}i,\:a=-\frac{15}{13}-\sqrt{2}i$
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Step-by-step Solution

How should I solve this problem?

  • Choose an option
  • Solve for a
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
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Solve the product $5\left(a+2\right)$

$5a+10=\frac{40}{a}+\frac{2a}{3}$

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$5a+10=\frac{40}{a}+\frac{2a}{3}$

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Unlock the first 3 steps of this solution

Learn how to solve problems step by step online. Solve the rational equation 5(a+2)=40/a+(2a)/3. Solve the product 5\left(a+2\right). Group the terms of the equation by moving the terms that have the variable a to the left side, and those that do not have it to the right side. Multiplying the fraction by -1. Multiplying the fraction by -1.

Final answer to the problem

$a=-\frac{15}{13}+\sqrt{2}i,\:a=-\frac{15}{13}-\sqrt{2}i$

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Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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Function Plot

Plotting: $5\left(a+2\right)+\frac{-40}{a}+\frac{-2a}{3}$

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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