Final answer to the problem
$6\left(x-\frac{1}{12}\right)^2+6\cdot \left(\frac{2}{3}-\frac{1}{144}\right)$
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Step-by-step Solution
Learn how to solve completing the square problems step by step online. Factor the expression 6x^2-x+4. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (6) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial x^2+-\frac{1}{6}x+\frac{1}{144}. Multiply the fraction and term in - \frac{1}{12}.
Final answer to the problem
$6\left(x-\frac{1}{12}\right)^2+6\cdot \left(\frac{2}{3}-\frac{1}{144}\right)$
