Simplify the expression $p\left(x\right)=\left(x+27\right)\left(x+5\right)\left(x-9\right)$

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Final answer to the problem

$p\left(x\right)=\left(x^2+32x+135\right)\left(x-9\right)$
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The product of two binomials of the form $(x+a)(x+b)$ is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: $(x+a)(x+b)=x^2+(a+b)x+ab$

Learn how to solve product of binomials with common term problems step by step online.

$p\left(x\right)=\left(x^2+\left(27+5\right)x+27\cdot 5\right)\left(x-9\right)$

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Learn how to solve product of binomials with common term problems step by step online. Simplify the expression p(x)=(x+27)(x+5)(x-9). The product of two binomials of the form (x+a)(x+b) is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: (x+a)(x+b)=x^2+(a+b)x+ab. Add the values 27 and 5. Multiply 27 times 5.

Final answer to the problem

$p\left(x\right)=\left(x^2+32x+135\right)\left(x-9\right)$

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Function Plot

Plotting: $p\left(x\right)-\left(x+27\right)\left(x+5\right)\left(x-9\right)$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Product of Binomials with Common Term

In special products, the product of two binomials that have a common term results in a trinomial, whose first term is the square of the common term, the second term is the product of the algebraic sum of the uncommon terms by the common term, and the third term is equal to the product of the uncommon terms. In other words: $(x+a)(x+b)=x^2+(a+b)x+ab$.

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