$\lim_{x\to4}\left(\frac{x^2+x-20}{x^2-7x+12}\right)$
$-6x+3\le-8x-7$
$-\left|4\cdot\left(-1\right)\right|^3+4$
$\frac{2}{7}x+8=\frac{2}{3}x$
$a^2+a-2>\frac{1}{2}$
$-11mn\:-2mn$
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