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Simplify the expression $f\left(x\right)=\left(x^4+1\right)\left(x^4-1\right)$

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 Solution

 Videos

Calculus - Learn how to take derivative using quotient rule by simplifying first, f(x)=x(1- 4/(x+3))

https://www.youtube.com/watch?v=Mqjiw5Ax_4w

Tutorial - Learn how evaluate the an absolute value function, f(x) = |3x - 1| + 2

https://www.youtube.com/watch?v=IgdnEUJPBQU

Tutorial - Solving a rational Equation ex2, 1/x + x/2 = (x+4)/ 2x

https://www.youtube.com/watch?v=a49VWDDgsMk

Algebra 2 - How to use the zero product property to solve for the intercepts, f(x) = 2x^2 + 7x - 30

https://www.youtube.com/watch?v=Km8b4e3Yb34

Tutorial - Evaluate an expression with one variable ex 1, x + 5; x = 3

https://www.youtube.com/watch?v=Mwv7NpccCmc

Pre-Calculus - Operations with functions f(x) = 2x -5 , g(x) = 2-x and f(x) = x^2+6 , g(x) root(1-x)

https://www.youtube.com/watch?v=rthRvbioYyU

 Function Plot

Plotting: $f\left(x\right)-\left(x^4+1\right)\left(x^4-1\right)$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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