Final answer to the problem
$y=e^{\left(-e^x+e^{-x}\right)}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for y
- Solve for x
- Find the derivative
- Solve by implicit differentiation
- Solve for y'
- Find dy/dx
- Derivative
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
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1
Take the variable outside of the logarithm
$e^{\ln\left(y\right)}=e^{\left(-e^x+e^{-x}\right)}$
2
Simplifying the logarithm
$y=e^{\left(-e^x+e^{-x}\right)}$
Final answer to the problem
$y=e^{\left(-e^x+e^{-x}\right)}$
