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Solve the product power $\left(2\left(1+15\left(4^2+1\right)\left(4^4+1\right)\left(4^8+1\right)\right)\right)^{0.5}$

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 Solution

 Videos

Algebra 2 - Simplifying a rational exponent with a rational base, (4/3)^(-1/2)

https://www.youtube.com/watch?v=8s2xAi_B4uc

Algebra 2 - Multiplying two exponents with rational powers, then simplifying, 2x^(2/5) . 6x^(1/4)

https://www.youtube.com/watch?v=ITQM50h5BlY

Tutorial - Learn how to determine th product of a monomial and a binomial ex 15, 4x^3(-2x^2 + 5x)

https://www.youtube.com/watch?v=JdZZtzCJzNI

Tutorial - How to solve a proportion with an expression over another ex 18, (c + 1)/(c - 2) = 4/7

https://www.youtube.com/watch?v=zdOYpQsQpHM

Factoring a perfect square trinomial with fractions, boo ex 31, x^2 + x + 1/4

https://www.youtube.com/watch?v=gHB8Lp_pFGI

Review factoring a trinomial using ac method, 3g^2 + 8g + 4 = 0

https://www.youtube.com/watch?v=nU6KWybcZng

 Function Plot

Plotting: $2147483647^{0.5}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Power of a product

The power of a product of factors is equal to the product of each factor to the same power: $\left(b\cdot c\right)^n=b^n\cdot c^n$.

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