Final answer to the problem
$y=\frac{1}{\sqrt[3]{x^{3}\left(-3x+C_0\right)}}$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Exact Differential Equation
- Linear Differential Equation
- Separable Differential Equation
- Homogeneous Differential Equation
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Load more...
Can't find a method? Tell us so we can add it.
1
Rewrite the differential equation in standard form
$\frac{dy}{dx}+\frac{y}{x}=\frac{x^4y^4}{x}$
Learn how to solve problems step by step online.
$\frac{dy}{dx}+\frac{y}{x}=\frac{x^4y^4}{x}$
Learn how to solve problems step by step online. Solve the differential equation xdy/dx+y=x^4y^4. Rewrite the differential equation in standard form. Simplify the fraction \frac{x^4y^4}{x} by x. We identify that the differential equation \frac{dy}{dx}+\frac{y}{x}=x^{3}y^4 is a Bernoulli differential equation since it's of the form \frac{dy}{dx}+P(x)y=Q(x)y^n, where n is any real number different from 0 and 1. To solve this equation, we can apply the following substitution. Let's define a new variable u and set it equal to. Plug in the value of n, which equals 4.
Final answer to the problem
$y=\frac{1}{\sqrt[3]{x^{3}\left(-3x+C_0\right)}}$
