Solve the equation with radicals $x^{-2}-6x^{-1}-16=0$

Step-by-step Solution

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Final answer to the problem

$x=-\frac{1}{2},\:x=\frac{1}{8}$
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Step-by-step Solution

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1

We need to isolate the dependent variable $x$, we can do that by simultaneously subtracting $-6x^{-1}-16$ from both sides of the equation

$x^{-2}=-\left(-6x^{-1}-16\right)$

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$x^{-2}=-\left(-6x^{-1}-16\right)$

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Learn how to solve radical equations and functions problems step by step online. Solve the equation with radicals x^(-2)-6x^(-1)+-16=0. We need to isolate the dependent variable x, we can do that by simultaneously subtracting -6x^{-1}-16 from both sides of the equation. Simplify the product -(-6x^{-1}-16). Applying the property of exponents, \displaystyle a^{-n}=\frac{1}{a^n}, where n is a number. Move everything to the left hand side of the equation.

Final answer to the problem

$x=-\frac{1}{2},\:x=\frac{1}{8}$

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Function Plot

Plotting: $x^{-2}-6x^{-1}-16$

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Answer Assistant

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Radical Equations and Functions

Equations that have variables inside a radical.

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