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Solve the quadratic equation $x^2-2x-528=0$

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Solution

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Final answer to the problem

$x=-22,\:x=24$
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Step-by-step Solution

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  • Solve for x
  • Find the derivative using the definition
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1

Factor the trinomial $x^2-2x-528$ finding two numbers that multiply to form $-528$ and added form $-2$

$\begin{matrix}\left(22\right)\left(-24\right)=-528\\ \left(22\right)+\left(-24\right)=-2\end{matrix}$

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$\begin{matrix}\left(22\right)\left(-24\right)=-528\\ \left(22\right)+\left(-24\right)=-2\end{matrix}$

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Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2-2x+-528=0. Factor the trinomial x^2-2x-528 finding two numbers that multiply to form -528 and added form -2. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Break the equation in 2 factors and set each factor equal to zero, to obtain simpler equations. Solve the equation (1).

Final answer to the problem

$x=-22,\:x=24$

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Function Plot

Plotting: $x^2-2x-528$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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