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Solve the quadratic equation $x^2-41x+400=0$

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Solution

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Final answer to the problem

$x=16,\:x=25$
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Step-by-step Solution

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  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
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  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
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1

Factor the trinomial $x^2-41x+400$ finding two numbers that multiply to form $400$ and added form $-41$

Learn how to solve quadratic equations problems step by step online.

$\begin{matrix}\left(-16\right)\left(-25\right)=400\\ \left(-16\right)+\left(-25\right)=-41\end{matrix}$

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Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2-41x+400=0. Factor the trinomial x^2-41x+400 finding two numbers that multiply to form 400 and added form -41. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Break the equation in 2 factors and set each factor equal to zero, to obtain simpler equations. Solve the equation (1).

Final answer to the problem

$x=16,\:x=25$

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Function Plot

Plotting: $x^2-41x+400$

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1
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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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