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Solve the differential equation $y^{\prime}y=x^3$

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Solution

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Videos

Calculus - Write the equation of a line tangent to a polynomial through a point, f(x) = x^3 + 2x

https://www.youtube.com/watch?v=wrM3iuM-tak

Algebra 2 - Learning to solve rational equations in math class ((x+3)/(x‐2)) + (5/(x^2‐4)) = 1

https://www.youtube.com/watch?v=y8p0Tpn3BcI

Algebra 2 - Learn to solve a rational equation by multiplying by the LCD (15/x)+((9x-7)/(x+2))=9

https://www.youtube.com/watch?v=BMSmvkWcVTU

Calculus - Derivative of inverse function given an equation, f(x) = x^3 + 7x; Find g'(8)

https://www.youtube.com/watch?v=cPvUjcS7N9w

Learn How to Solve a Polynomial Using the Difference of Two Cubes

https://www.youtube.com/watch?v=hRoKqnjBIDM

Pre-Calculus - Solving trigonometric equations ex 8, cosx + sinx.tanx = 2

https://www.youtube.com/watch?v=LasCSb_b4OY

Function Plot

Plotting: $y=\sqrt{2\left(\frac{x^{4}}{4}+C_0\right)},\:y=-\sqrt{2\left(\frac{x^{4}}{4}+C_0\right)}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

$\frac{dy}{dx}=y^2-9$

$\frac{dy}{dx}=y^2-4$

$\frac{dy}{dx}=y-y^2$

$\frac{dy}{dx}=y\left(y+2\right)$

$\frac{dy}{dx}=\left(1+e^{-x}\right)\left(y^2-1\right)$

$\frac{dy}{dx}=\frac{x}{2x-y}$

$\frac{dy}{dx}=y\left(1-y\right)$

Main Topic: Integrals of Polynomial Functions

Integrals of polynomial functions.

Used Formulas

See formulas (1)

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