Final answer to the problem
$y=\left(2x+3\right)^5\sqrt[3]{x-1}\sqrt{x^2+4x+4-4^{7}}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Differential
- Find the derivative
- Find the integral
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
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1
Factor the polynomial $x^2+4x$. Add and subtract $\left(\frac{b}{2}\right)^2$, replacing $b$ by it's value $4$
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$y=\left(2x+3\right)^5\sqrt[3]{x-1}\sqrt{x^2+4x+\left(\frac{4}{2}\right)^2- \left(\frac{4}{2}\right)^2^{7}}$
Learn how to solve problems step by step online. Solve the equation with radicals y=(2x+3)^5(x-1)^(1/3)(x^2+4x)^(7/2). Factor the polynomial x^2+4x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value 4. Divide 4 by 2. Divide 4 by 2. Calculate the power 2^2.
Final answer to the problem
$y=\left(2x+3\right)^5\sqrt[3]{x-1}\sqrt{x^2+4x+4-4^{7}}$
