Final answer to the problem
$y=\frac{\left(x^2-3x+7\right)x^3\left(16\left(x-\frac{1}{4}\right)^2+3\right)^3}{64}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Differential
- Find the derivative
- Find the integral
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
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1
Factor the polynomial $\left(4x^3-2x^2+x\right)$ by it's greatest common factor (GCF): $x$
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$y=\left(x^2-3x+7\right)\left(x\left(4x^2-2x+1\right)\right)^3$
Learn how to solve problems step by step online. Solve the equation y=(x^2-3x+7)(4x^3-2x^2x)^3. Factor the polynomial \left(4x^3-2x^2+x\right) by it's greatest common factor (GCF): x. The power of a product is equal to the product of it's factors raised to the same power. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (4) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2.
Final answer to the problem
$y=\frac{\left(x^2-3x+7\right)x^3\left(16\left(x-\frac{1}{4}\right)^2+3\right)^3}{64}$
