Final answer to the problem
$y=\frac{1}{2}\ln\left(\frac{a^2-x^2}{a^2+x^2}\right)$
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Step-by-step Solution
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- Factor by completing the square
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1
Using the power rule of logarithms: $\log_a(x^n)=n\cdot\log_a(x)$
$y=\frac{1}{2}\ln\left(\frac{a^2-x^2}{a^2+x^2}\right)$
Final answer to the problem
$y=\frac{1}{2}\ln\left(\frac{a^2-x^2}{a^2+x^2}\right)$
