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Solve the logarithmic equation $y=\ln\left(\sqrt{4-x^2}\right)$

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e
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ln
log
log
lim
d/dx
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θ
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>
<
>=
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sin
cos
tan
cot
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asin
acos
atan
acot
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sinh
cosh
tanh
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sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Algebra 2 - Using quotient property of logarithms to solve a logarithmic equation, log(5) -log(2x)=1

https://www.youtube.com/watch?v=FuybMptg-r8

Algebra 2 Apply the equality property of logarithms to solve an equation, log13 (x^2 -4)=log13 (3x)

https://www.youtube.com/watch?v=nw9V_xx2ms0

Tutorial-How to solve a logarithmic equation with an extraneous solution ex20, 4 log3(2) -2log3(x)=1

https://www.youtube.com/watch?v=NJg15fq48vU

Algebra 2 - Solving an equation by using the square root property - Math help (y-4)^2 + 7 = 0

https://www.youtube.com/watch?v=LAi0djUhPh4

Pre-Calculus - Rewriting a exponential equation to solve using one to one properties (2/3)^x = 4/9

https://www.youtube.com/watch?v=wLewO22uTX4

Applying equality property of logarithms to solve by factoring, log4 (x^2 -4)=log4 (-x+2)

https://www.youtube.com/watch?v=z7AHkGgPHxQ

Function Plot

Plotting: $y-\ln\left(\sqrt{4-x^2}\right)$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Logarithmic Equations

Are those equations in which the unknown variable appears within a logarithm.

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