Solve the differential equation $y\frac{dy}{dx}\ln\left(x\right)=\frac{\left(y+1\right)^2}{x}$

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Final answer to the problem

$\ln\left|y+1\right|+\frac{1}{y+1}=\ln\left|\ln\left|x\right|\right|+C_0$
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Step-by-step Solution

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  • Exact Differential Equation
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Group the terms of the differential equation. Move the terms of the $y$ variable to the left side, and the terms of the $x$ variable to the right side of the equality

Learn how to solve integrals by partial fraction expansion problems step by step online.

$\frac{y}{\left(y+1\right)^2}dy=\frac{1}{\ln\left(x\right)}\frac{1}{x}dx$

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Learn how to solve integrals by partial fraction expansion problems step by step online. Solve the differential equation yln(x)dy/dx=((y+1)^2)/x. Group the terms of the differential equation. Move the terms of the y variable to the left side, and the terms of the x variable to the right side of the equality. Simplify the expression \frac{y}{\left(y+1\right)^2}dy. Simplify the expression \frac{1}{\ln\left(x\right)}\frac{1}{x}dx. Integrate both sides of the differential equation, the left side with respect to y, and the right side with respect to x.

Final answer to the problem

$\ln\left|y+1\right|+\frac{1}{y+1}=\ln\left|\ln\left|x\right|\right|+C_0$

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Function Plot

Plotting: $y\frac{dy}{dx}\ln\left(x\right)+\frac{-y^2-2y-1}{x}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Integrals by Partial Fraction Expansion

The partial fraction decomposition or partial fraction expansion of a rational function is the operation that consists in expressing the fraction as a sum of a polynomial (possibly zero) and one or several fractions with a simpler denominator.

Used Formulas

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