Final answer to the problem
$y=\sqrt{14x+7},\:y=-\sqrt{14x+7}$
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Step-by-step Solution
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- Solve for y
- Solve for x
- Find the derivative
- Solve by implicit differentiation
- Solve for y'
- Find dy/dx
- Derivative
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
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1
Removing the variable's exponent
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$\sqrt{y^2}=\pm \sqrt{14x+7}$
Learn how to solve equations problems step by step online. Solve the equation y^2=14x+7. Removing the variable's exponent. Cancel exponents 2 and 1. As in the equation we have the sign \pm, this produces two identical equations that differ in the sign of the term \sqrt{14x+7}. We write and solve both equations, one taking the positive sign, and the other taking the negative sign. Combining all solutions, the 2 solutions of the equation are.
Final answer to the problem
$y=\sqrt{14x+7},\:y=-\sqrt{14x+7}$
