Exercise

$4x^2-9$

Step-by-step Solution

1

Find the derivative of $4x^2-9$ using the definition. Apply the definition of the derivative: $\displaystyle f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}$. The function $f(x)$ is the function we want to differentiate, which is $4x^2-9$. Substituting $f(x+h)$ and $f(x)$ on the limit, we get

$\lim_{h\to0}\left(\frac{4\left(x+h\right)^2-9-\left(4x^2-9\right)}{h}\right)$
2

Multiply the single term $-1$ by each term of the polynomial $\left(4x^2-9\right)$

$\lim_{h\to0}\left(\frac{4\left(x+h\right)^2-9-4x^2+9}{h}\right)$
3

Add the values $-9$ and $9$

$\lim_{h\to0}\left(\frac{4\left(x+h\right)^2-4x^2}{h}\right)$
4

Expand the expression $\left(x+h\right)^2$ using the square of a binomial: $(a+b)^2=a^2+2ab+b^2$

$\lim_{h\to0}\left(\frac{4\left(x^{2}+2xh+h^{2}\right)-4x^2}{h}\right)$
5

Multiply the single term $4$ by each term of the polynomial $\left(x^{2}+2xh+h^{2}\right)$

$\lim_{h\to0}\left(\frac{4x^{2}+8xh+4h^{2}-4x^2}{h}\right)$
6

Simplifying

$\lim_{h\to0}\left(\frac{8xh+4h^{2}}{h}\right)$
7

Expand the fraction $\frac{8xh+4h^{2}}{h}$ into $2$ simpler fractions with common denominator $h$

$\lim_{h\to0}\left(\frac{8xh}{h}+\frac{4h^{2}}{h}\right)$
8

Simplify the resulting fractions

$\lim_{h\to0}\left(8x+4h\right)$
9

Evaluate the limit $\lim_{h\to0}\left(8x+4h\right)$ by replacing all occurrences of $h$ by $0$

$8x$

Final answer to the exercise

$8x$

Try other ways to solve this exercise

  • Find the derivative using the definition
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Prove from LHS (left-hand side)
  • Load more...
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