Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Factor
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor by completing the square
- Find the roots
- Find break even points
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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=4$, $b=12$ and $c=-16$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
Learn how to solve differential calculus problems step by step online.
$x=\frac{-12\pm \sqrt{12^2-4\cdot 4\cdot -16}}{2\cdot 4}$
Learn how to solve differential calculus problems step by step online. Solve the quadratic equation 4x^2+12x+-16=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=4, b=12 and c=-16. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 20 and -12.