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Find the break even points of the expression $\left(y\ln\left(y\right)+e^{-xy}\right)dx+\frac{1}{y}+x\ln\left(y\right)\cdot dy=0=0$

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Solving: $\left(y\ln\left(y\right)+e^{-xy}\right)dx+\frac{1}{y}+x\ln\left(y\right)\cdot dy=0=0$

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Integral de dx entre 1 + cos x , multiplicando por conjugado y aplicando identidades

https://www.youtube.com/watch?v=ZepYdR310Sk

When a is greater than one factor the polynomial 2y^2 + y - 1

https://www.youtube.com/watch?v=wghtzUjyG7A

_-substitution: definite integral of exponential function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=1ct7LUx23io

Algebra 2 - Finding the vertex of a quadratic function y = 2x^2 + 2x + 1

https://www.youtube.com/watch?v=V2udel2WylU

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

See formulas (1)

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