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Find the break even points of the expression $x\left(3x+20\right)=7$

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sin
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asin
acos
atan
acot
asec
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sinh
cosh
tanh
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asinh
acosh
atanh
acoth
asech
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Solution

Videos

Algebra 2 - Learn to solve a rational equation by multiplying by the LCD (15/x)+((9x-7)/(x+2))=9

https://www.youtube.com/watch?v=BMSmvkWcVTU

Calculus: Derivatives 2 | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=ay8838UZ4nM

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

How to take the derivative using chain rule with natural log and cosine

https://www.youtube.com/watch?v=bbK7KtEeULo

Learn how to simplify an expression to find the derivative

https://www.youtube.com/watch?v=AJeW23c_BI8

How to find the derivative with exponential functions base 5

https://www.youtube.com/watch?v=yPAaO-FKSVQ

Function Plot

Plotting: $x\left(3x+20\right)-7$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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